3x^2+60+2x^2-25=180

Solution for 3x^2+60+2x^2-25=180 equation:

3x^2+60+2x^2-25=180

We move all terms to the left:

3x^2+60+2x^2-25-(180)=0

We add all the numbers together, and all the variables

5x^2-145=0

a = 5; b = 0; c = -145;
Δ = b2-4ac
Δ = 02-4·5·(-145)
Δ = 2900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2900}=\sqrt{100*29}=\sqrt{100}*\sqrt{29}=10\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{29}}{2*5}=\frac{0-10\sqrt{29}}{10}
=-\frac{10\sqrt{29}}{10}
=-\sqrt{29}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{29}}{2*5}=\frac{0+10\sqrt{29}}{10}
=\frac{10\sqrt{29}}{10}
=\sqrt{29}
$